Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 12 - Temperature and Heat - Problems - Page 342: 2



Work Step by Step

We know: T = t+ 273.15 where T is the temperature in Kelvin and t is the temperature in Celsius. Then: t=$ (312.0- 273.15)^{\circ}C= 38.85^{\circ}C$ To convert the temperature to Fahrenheit: We use the relation: F= $\frac{9}{5}C+32$ Which gives: F= $\frac{9}{5}×38.85+32$ =101.93°F$\approx$102°F
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