## Physics (10th Edition)

$102^{\circ}F$
We know: T = t+ 273.15 where T is the temperature in Kelvin and t is the temperature in Celsius. Then: t=$(312.0- 273.15)^{\circ}C= 38.85^{\circ}C$ To convert the temperature to Fahrenheit: We use the relation: F= $\frac{9}{5}C+32$ Which gives: F= $\frac{9}{5}×38.85+32$ =101.93°F$\approx$102°F