Answer
Option (c) is correct.
Work Step by Step
Recall that $F=Y\frac{\Delta L}{L_{0}}A$
where $\Delta L$ is the stretch in length, $L_{0}$ is the original length, $Y$ is the Young's modulus, $A$ is the cross-sectional area on which the force required to stretch $F$ is applied.
Rearranging, we get $\Delta L=\frac{FL_{0}}{YA}$
For both the cylinders $F,L_{0}$ and $Y$ are the same.
As cylinder $B$ is hollow, its cross-sectional area is small and therefore, according to the above equation, $\Delta L$ or stretch is more for $B$ than that in cylinder $A$.
The correct option is (c).
