Answer
A) 198.5 N
B) 40.91°
Work Step by Step
Using trigonometry to find the angle and magnitude of the vector:
a) $F=\sqrt {130^2+150^2}=198.5$
b) $\theta= \tan^{-1}(130/150)=40.91^{\circ}$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 1 - Introduction and Mathematical Concepts - Problems - Page 22: 40
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