Answer
$7.9$ m
$21.4^{\circ}$
Work Step by Step
We can subtract 23 from 90 to get the angle of the triangle.
$90^{\circ}-23^{\circ}=67^{\circ}$
Next, we can use law of cosine to get the magnitude of the resutant vector
$c^{2}=6^{2}+8^{2}-2\times6\times8cos67^{\circ}$
$c=7.9$ m
We can use the law of sines to find the angle.
$sin\theta=\frac{8sin67^{\circ}}{7.91}$
$\theta=68.6^{\circ}$
We can subtract 68.6 from 90 to get the angle the vector makes with the x-axis.
$90^{\circ}-68.6^{\circ}=21.4^{\circ}$
