Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 212: 121c

Answer

$F = \frac{1.5\times 10^6}{\sqrt{100+1.5~t}}~~~N$

Work Step by Step

We can find an expression for the speed of the train: $K = K_0+P~t$ $\frac{1}{2}mv^2 = \frac{1}{2}mv_0^2+P~t$ $v^2 = v_0^2+\frac{2~P~t}{m}$ $v = \sqrt{v_0^2+\frac{2~P~t}{m}}$ $v = \sqrt{(10~m/s)^2+\frac{(2)(1.5\times 10^6~W)~t}{2.06\times 10^6~kg}}$ $v = \sqrt{100+1.5~t}~~m/s$ We can find an expression for the force: $F~v = P$ $F = \frac{P}{v}$ $F = \frac{1.5\times 10^6}{\sqrt{100+1.5~t}}~~~N$
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