Answer
$T = 4.5N$
Work Step by Step
$v^2_B$ from part (a) is $4.9m/s$
$T = mg + \frac{mv^2_B}{l}$
$T = (0.092kg \times 9.8m/s^2) + \frac{0.092kg \times 4.9^2_{m/s}}{0.62m}$
$T = 4.5N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 208: 75b
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