Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 204: 23b

Answer

$$ v_{b}=2.42 \mathrm{m} / \mathrm{s}$$

Work Step by Step

In this case, the total mechanical energy is shared between kinetic $\frac{1}{2} m v_{b}^{2}$ and potential $m g y_{b} .$ We note that $y_{b}=2 r$ where $r=L-d=0.450 \mathrm{m} .$ Energy conservation leads to $$ m g L=\frac{1}{2} m v_{b}^{2}+m g y_{b} $$ $\text { which yields } v_{b}=\sqrt{2 g L-2 g [2r] ]}=2.42 \mathrm{m} / \mathrm{s}$
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