Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems: 1


Spring Constant $K= 89N/cm$.

Work Step by Step

We know that $P.E_{spring}=\frac{1}{2}Kx^2$ Putting the values, we get $25=\frac{1}{2}K(.075)^2$ $2\times25=k(.005625)$ $\frac{50}{.005625}=K$ or $K=8888.9$ $K=8.9\times10^3\frac{N}{m}$ As $1m=100cm$ Hence $K=8.9\times10^3\frac{N}{100cm}$ $K=89\frac{N}{cm}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.