Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 170: 2

Answer

$K.E$= $1.82\times10^{13}J$

Work Step by Step

As we know that $K.E$=$\frac{1}{2}$$m$$v^{2}$ Putting the values, we get $K.E$=$\frac{1}{2}(2.9\times10^5)(11.2\times10^3)^2$ $K.E$=$1.45\times10^{5}\times11.2\times11.2\times10^{6}$ $K.E$=$181.888\times10^{11}$ $K.E$=$1.81888\times10^{2}\times10^{11}$ Or after rounding it off, we get $K.E$=$1.82\times10^{13}J$
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