Answer
0.107 $m/s^2$
Work Step by Step
The slope is 200m and with the standard skis it takes 61s to make it down. Since the skier starts at rest, we know that v0 = 0 m/s. Then we can use the equation :
$ x = x_{0} + v_{0}t + (1/2)at^2 $ where we set x = 200, x0 = 0, v0 = 0 and we are solving for the acceleration. We find that it is a = 0.107 $m/s^2$
