Answer
The direction of the acceleration is down the plane.
Work Step by Step
Let the direction down the plane be the positive direction.
We can find the acceleration:
$mg~sin~\theta+ mg~\mu_k~cos~\theta = ma$
$a = g~(sin~\theta+ \mu_k~cos~\theta)$
$a = (9.8~m/s^2)~(sin~60^{\circ}+ 0.20~cos~60^{\circ})$
$a = 9.5~m/s^2$
Since the acceleration is positive, the direction of the acceleration is down the plane.