Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 6 - Force and Motion-II - Problems - Page 146: 73d

Answer

The direction of the acceleration is down the plane.

Work Step by Step

Let the direction down the plane be the positive direction. We can find the acceleration: $mg~sin~\theta+ mg~\mu_k~cos~\theta = ma$ $a = g~(sin~\theta+ \mu_k~cos~\theta)$ $a = (9.8~m/s^2)~(sin~60^{\circ}+ 0.20~cos~60^{\circ})$ $a = 9.5~m/s^2$ Since the acceleration is positive, the direction of the acceleration is down the plane.
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