Answer
$-(2.20\times10^2)$ m/s dC
Work Step by Step
Differentiating $v_t$ with respect to C, we obtain $dv_t=1/2 √2Fg/Aρ C^-3/2 dC$
put values $dv_t=1/2 √(2(510))/(1.20)(1.30) (0.150)^-3/2 dC$
We get, $-(2.20\times10^2)$ m/s dC
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 6 - Force and Motion-II - Problems - Page 143: 40b
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