Chapter 5 - Force and Motion-I - Problems - Page 120: 52

Velocity of the man V = 5.11468 m/s

Acceleration of man a = (m2-m1)g/m1+m2 Here m2 is the mass of the man m1 is the mass of the sandbag Substituting given values we get a = 1.308 m/s^2 We know that V$^2$ -u$^2$ = 2aS Here u =0 S = 10 a = 1.308m/s$^2$ Substituting values we get Velocity of the man V = 5.11468 m/s