Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems: 17c


4.9 $m/s^2$

Work Step by Step

If the cord is cut, there is no longer a Tension so the only force acting in the x direction (along the plane) is that of Fg,x. In part a we found that this is equal to Fgsin(30) = 41.7N. This is the force propelling the block down the ramp and since the block has a mass of 8.5kg and F = ma then a = F/m so a = 41.7N/8.5kg = 4.9 $m/s^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.