Answer
$$60 \mathrm{\ MeV}$$
Work Step by Step
$$K_{\mathrm{Nd}}=\frac{M_{\mathrm{Ge}}}{M_{\mathrm{Nd}}+M_{\mathrm{Ge}}} Q=\frac{83 \mathrm{u}}{153 \mathrm{u}+83 \mathrm{u}}(170 \mathrm{MeV})=60 \mathrm{\ MeV}$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 43 - Energy from the Nucleus - Problems - Page 1331: 17c
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