Answer
19 m/s
Work Step by Step
Centripetal acceleration $a_{c}=\frac{v^{2}}{R}$
That is, $7.0g=\frac{v^{2}}{5.0\,m}$
$\implies v^{2}=7.0g\times5.0\,m=35\,m\times9.8\,m/s^{2}$
Or $v=\sqrt {35\times9.8\,m^{2}/s^{2}}=19\,m/s$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 90: 92a
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