Answer
Returning to the closer mirror $\mathrm{M}_1$, there is an image $I_5$ that is $90 \mathrm{~cm}$ behind the mirror (since $I_3$ is $90 \mathrm{~cm}$ in front of it). The distances for $I_5$ is $100 \mathrm{~cm}=1.0$ $\mathrm{m}$.
Work Step by Step
Returning to the closer mirror $\mathrm{M}_1$, there is an image $I_5$ that is $90 \mathrm{~cm}$ behind the mirror (since $I_3$ is $90 \mathrm{~cm}$ in front of it). The distances for $I_5$ is $100 \mathrm{~cm}=1.0$ $\mathrm{m}$.
