Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 34 - Images - Problems - Page 1042: 82b

Answer

$-0.27$

Work Step by Step

We can use our answer from part A along with the given information to find the overall lateral magnification, $M$. First we consider equation 34-11: $M=m_1*m_2$ We note that $m=-i/p$, to obtain: $M=(-i_1/p_1)*(-i_2/p_2)$ $M=(-(-3.4cm)/8.0cm)*(9.8cm/15.4cm)$ $M=-0.27$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.