Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 34 - Images - Problems - Page 1042: 81b

Answer

$+6.0$

Work Step by Step

We can use our answer from part A along with the given information to find the overall lateral magnification, $M$. First we consider equation 34-11 $M=m_1*m_2$ We note that $m=-i/p$, to obtain: $M=(-i_1/p_1)*(-i_2/p_2)$ $M=(-(24cm)/12cm)*(-24cm/8cm)$ $M=+6.0$
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