Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 34 - Images - Problems - Page 1038: 7

Answer

10.5 cm

Work Step by Step

Linear magnification, m= $-\frac{v}{u}$ = 2.50 where v is the image distance and u the object distance. This implies v= -2.50u. Mirror equation tells us that $\frac{1}{v}+\frac{1}{u}=\frac{2}{R}$ where R is the radius of curvature. Substituting the value of v and R, we have $\frac{1}{-2.50u}+\frac{1}{u}=\frac{2}{-35.0cm}$ Or $\frac{1-2.50}{-2.50u}=\frac{2}{-35.0 cm}$ ⇒ u=$ \frac{(1-2.50)(-35.0cm)}{2\times(-2.50)}$= -10.5 cm So the distance between the mirror and the face is 10.5 cm.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.