Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 33 - Electromagnetic Waves - Problems - Page 1004: 47

Answer

The index of refraction of the glass is $~~1.48$

Work Step by Step

We can use Snell's law to find $n_2$: $n_2~sin~\theta_2 = n_1~sin~\theta_1$ $n_2 = \frac{n_1~sin~\theta_1}{sin~\theta_2}$ $n_2 = \frac{1.00~sin~32.0^{\circ}}{sin~21.0^{\circ}}$ $n_2 = 1.48$ The index of refraction of the glass is $~~1.48$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.