Answer
$\tau=1.49 \times 10^{-4} \mathrm{~N} \cdot \mathrm{m} $
Work Step by Step
Using Formula,
$
\tau=\mu_{\mathrm{rod}} B \sin \theta=(2700 \mathrm{~A} / \mathrm{m})(0.06 \mathrm{~m}) \pi(0.003 \mathrm{~m})^2(0.035 \mathrm{~T}) \sin \left(68^{\circ}\right)=1.49 \times 10^{-4} \mathrm{~N} \cdot \mathrm{m}
$
We have used the fact that the volume of a cylinder is its length times its cross sectional area.
