Answer
20.8 mJ/T
Work Step by Step
Magnetization $M=\frac{Magnetic\,dipole\,moment}{Volume\,}$
Volume of a cylinder is given by $\pi r^{2}L$.
Therefore, magnetic dipole moment= $M\times\pi r^{2}L$
$=(5.30\times10^{3}\,A/m)\times\pi(0.500\times10^{-2}m)^{2}\times5.00\times10^{-2}m$
$=2.08\times10^{-2}\,Am^{2}=20.8\,mJ/T$
