Answer
$7.2\times10^{12}\,V/m\cdot s$
Work Step by Step
Given/known: $i_{d}=2.0\,A,$ $\varepsilon_{0}=8.854\times10^{-12}\,F/m,$ $r=0.10\,m$
Recall: $i_{d}=\varepsilon_{0}A\frac{dE}{dt}$ or $\frac{dE}{dt}=\frac{i_{d}}{\varepsilon_{0}\times\pi r^{2}}$
Result: $\frac{dE}{dt}=\frac{2.0\,A}{(8.854\times10^{-12}\,F/m)\times\pi (0.10\,m)^{2}}=7.2\times10^{12}\,V/m\cdot s$