Answer
Larger than that in circuit 2.
Work Step by Step
The induced emf of a moving bar is equal to $$\varepsilon = Blv$$ The magnetic field is the same for both experiments, so $B$ is unchanged. The velocity of the bar is the same for both experiments, so $v$ is unchanged. However, the length of the bar must be larger in experiment 1 than experiment 2. Therefore, the induced emf in experiment 1 would be larger than the induced emf in experiment 2.
