Answer
$L=0.600$ mH
Work Step by Step
We know that;
$emf=L\frac{dI}{dt}$
This can be rearranged as:
$L=\frac{emf}{\frac{di}{dt}}$
Next, substitute the values and solve:
$L=\frac{0.003}{5}=0.0006H=0.600\times 10^{-3}=0.600mH$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 30 - Induction and Inductance - Problems - Page 902: 98a
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