Answer
The magnitude of the emf induced in the loop is $~~11~mV$
Work Step by Step
We can find the emf induced in the loop:
$\mathscr{E} = -\frac{d\Phi}{dt}$
$\mathscr{E} = -A~\frac{dB}{dt}$
$\mathscr{E} = -(\pi~r^2)~(\frac{dB}{dt})$
$\mathscr{E} = -(\pi)~(0.12~m)^2~(\frac{0.50~T}{2.0~s})$
$\mathscr{E} = -11~mV$
The magnitude of the emf induced in the loop is $~~11~mV$
