Answer
We can rank the segments according to the magnitude of the average electric field in them:
$b \gt d \gt a = c = e$
Work Step by Step
Across sections $a, c,$ and $e$, the potential difference is zero, so the electric field is zero.
Across sections $b$ and $d$, the potential difference is non-zero, so the electric field is non-zero.
Note that in general: $\Delta V = i~R$
Since $R_1 \gt R_2$, the magnitude of the potential difference across $R_1$ is greater than the magnitude of the potential difference across $R_2$. Therefore, the magnitude of the electric field in section $b$ is greater than the magnitude of the electric field in section $d$
We can rank the segments according to the magnitude of the average electric field in them:
$b \gt d \gt a = c = e$
