Answer
$4.605 \tau$
Work Step by Step
We need $1-e^{-x}= 0.99$ . Thus, $e^{ -x } = 0.01$, so x = $\ln 100$ = $4.605 \tau$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 27 - Circuits - Problems - Page 799: 59
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