Answer
$V_2 = -9.0~V$
Work Step by Step
We can combine the two resistors in parallel into the equivalent resistance of $1.0~\Omega$
We can assume that the current flows counterclockwise.
We can use the loop rule to find the current:
$12-i-2i-2i-5.0-2i = 0$
$7i = 7.0$
$i = 1.0~A$
We can start at ground and move clockwise to the point marked $V_2$:
$V_2 = 0+(1.0~A)(1.0~\Omega)-12~V+(1.0~A)(2.0~\Omega)$
$V_2 = -9.0~V$
