Answer
$n=7.5\times10^{21}$ electrons
Work Step by Step
As we know that
$q=ne$
or $n=\frac{q}{e}$
We plug in the known values to obtain:
$n=\frac{1.2\times10^3}{1.602\times10^{-19}}$
$n=7.5\times10^{21}$ electrons
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