Answer
$Q=1.09\times 10^3J$
Work Step by Step
We know that;
$Q=nC_P\Delta T$
and $C_p=\frac{7}{2}R$
Hence, $Q=n(\frac{7}{2}R)\Delta T$.
We plug in the known values to obtain:
$Q=0.375(\frac{7}{2})(8.31)(100)=1.09\times 10^3J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 19 - The Kinetic Theory of Gases - Problems - Page 580: 52b
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