Answer
$$0.048 \mathrm{g} / \mathrm{s}$$
Work Step by Step
from part (a)
$$P_{\text {cond }}= 16 \mathrm{J} / \mathrm{s}$$
Using Table $18-4,$ the rate at which ice melts is
$$\left|\frac{d m}{d t}\right|=\frac{P_{\text {cond }}}{L_{F}}=\frac{16 \mathrm{J} / \mathrm{s}}{333 \mathrm{J} / \mathrm{g}}=0.048 \mathrm{g} / \mathrm{s}$$
