Answer
$$16 \mathrm{\ J} / \mathrm{s}$$
Work Step by Step
call to mind that a change in Kelvin temperature is numerically parallel to a change on the Celsius scale, we find that the rate of heat conduction is
$$P_{\text {cond }}=\frac{k A\left(T_{H}-T_{C}\right)}{L}=\frac{(401 \mathrm{W} / \mathrm{m} \cdot \mathrm{K})\left(4.8 \times 10^{-4} \mathrm{m}^{2}\right)\left(100^{\circ} \mathrm{C}\right)}{1.2 \mathrm{m}}=16 \mathrm{\ J} / \mathrm{s}$$
