Answer
Rope $B$ was shorter
Work Step by Step
İf system is in equilibrium then net torque is zero on center of mass. The direction of torques created by A and B are in opposite direction so the magnitudes must be same in order to create balanced torque. Therefore,
$t_{A}=t_{B}$
Torques are the same but perpendicular distances are not the same as point A is more farther from the center of mass. Therefore, the force acting on rope B must be bigger than the force created by rope A to compensate for the difference in distances.
So,
$F_{B} > F_{A}$
Because force created by rope $B$ is bigger, the stretch of rope $B$ will be greater. Therefore, if they are of the same length, then rope $B$ must be shorter at the start.
