Answer
The magnitude of the force on the bridge from the support at the nearer end is $~~1900~N$
Work Step by Step
In part (a), we found that the magnitude of the force on the bridge from the support at the farther end is $~~1500~N$
The sum of the forces on the bridge from the supports is equal in magnitude to the total weight of the bridge and the person.
We can find the magnitude of the force on the bridge from the support at the nearer end.
$F+1500~N = (73~kg)(9.8~m/s^2)+2700~N$
$F = (73~kg)(9.8~m/s^2)+2700~N - 1500~N$
$F = 1900~N$
The magnitude of the force on the bridge from the support at the nearer end is $~~1900~N$
