Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 1 - Measurement - Problems - Page 8: 1b

Answer

$1.62 \times 10^8 \pi \text{ or } S_{a} \approx 5.10 \times 10^8 \text{km}^2$

Work Step by Step

Earth's radius $r \approx 6.37 \times 10^6$ meters. Remember that 1 kilometer = 1000 meters. Then the radius in kilometers is $$r \approx 6.37 \times 10^6 \text{meters} \times \cfrac{1 \text{ kilometers}}{1000 {\text{ meters}}}$$ The units cancel, $$ \approx \frac{6.37 \times 10^6 \text{ kilometers}}{1000} = 6.37 \times 10^3 \text{ kilometers}$$ The Surface Area of a Sphere is $A_{S}= 4\pi r^2 $ then after rounding for significant figures: $$A_{S}= 4\pi ( 6.37 \times 10^3 \text{ kilometers)}^2 = 1.62 \times 10^8 \pi$$ $$ = 5.10 \times 10^3 \text{ km}^2$$
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