## Essential University Physics: Volume 1 (3rd Edition)

Using conservation of momentum, we find the x and y components of the velocity to be as follows: $v_{px}=\frac{(5)(1.6)-4cos(33^{\circ})(1.4)}{1}=3.3$ $v_{py}=\frac{(1.4)(4)(sin33^{\circ})}{1}=-3.05$ We find the speed to be: $v=\sqrt{3.3^3+(-3.05)^2}=4.49 \ Mm/s$ We find the angle: $\theta = tan^{-1}(-3.05/3.3)=-43^{\circ}$