Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Section 9.1 - Center of Mass - Example: 9.3

Answer

$\frac{2L}{3}$

Work Step by Step

We know: $\frac{dm}{M} = \frac{2xdx}{L^2}$ We obtain the following integral from this: $x_{cm} = \frac{1}{M} \int xdm = \frac{2}{L^2} \int_0^Lx^2dx =\frac{2L}{3} $
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