Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Exercises and Problems - Page 166: 87


$(4R/3\theta)sin(.5\theta)$ from the tip of the slice.

Work Step by Step

We know that the area is: $A=\frac{\pi r^2 \theta}{2\pi}=\frac{ r^2 \theta}{2}$ Thus, we find that the center of mass, using the geometric center of the slice of pizza, is: $y_{cm}=\frac{.67r^3sin.5\theta}{ r^2 (.5\theta)}$ $y_{cm}=(4R/3\theta)sin(.5\theta)$ from the tip of the slice.
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