## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 9 - Exercises and Problems - Page 166: 87

#### Answer

$(4R/3\theta)sin(.5\theta)$ from the tip of the slice.

#### Work Step by Step

We know that the area is: $A=\frac{\pi r^2 \theta}{2\pi}=\frac{ r^2 \theta}{2}$ Thus, we find that the center of mass, using the geometric center of the slice of pizza, is: $y_{cm}=\frac{.67r^3sin.5\theta}{ r^2 (.5\theta)}$ $y_{cm}=(4R/3\theta)sin(.5\theta)$ from the tip of the slice.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.