Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Exercises and Problems: 56

Answer

$F=3mN$

Work Step by Step

As the rate of change of mass is given as: $\frac{dm}{dt}=\frac{12}{2}=6\frac{g}{s}$ Now we can find the force: $F=\frac{dp}{dt}$ $F=\frac{d}{dt}(mv)$ $\implies F=v\frac{dm}{dt}$ We plug in the known values to obtain: $F=50\times 6 \ dyne$ $F=3mN$
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