Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Exercises and Problems - Page 164: 50


$v=2.69\times10^5\ m/s$ $\theta=18^{\circ}$

Work Step by Step

We first find the speed. Since momentum is conserved, it follows: $238(5\times10^5)=4(1.4\times10^7)+234v$ $v=2.69\times10^5\ m/s$ We now find the angle: $\theta = tan^{-1}(\frac{4(1.4\times10^7)\times sin22}{2.69\times10^5\times234})$ $\theta=18^{\circ}$
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