## Essential University Physics: Volume 1 (3rd Edition)

$v=2.69\times10^5\ m/s$ $\theta=18^{\circ}$
We first find the speed. Since momentum is conserved, it follows: $238(5\times10^5)=4(1.4\times10^7)+234v$ $v=2.69\times10^5\ m/s$ We now find the angle: $\theta = tan^{-1}(\frac{4(1.4\times10^7)\times sin22}{2.69\times10^5\times234})$ $\theta=18^{\circ}$