Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Section 8.4 - Gravitational Energy - Example - Page 135: 8.4

Answer

The answer is below.

Work Step by Step

We use the following equation: $W = \Delta U_{12} = GM_Em(\frac{1}{r_1}-\frac{1}{r_2})$ Thus, we find: A) $W = \Delta U_{12} = 4.4\times 10^{18}(\frac{1}{6.37 \times 10^6}-\frac{1}{4.22 \times 10^7})= 5.8 \times 10^{11} \ J$ B) $W = \Delta U_{12} = 4.4\times 10^{18}(\frac{1}{4.22 \times 10^7}-\frac{1}{3.8\times 10^8})= 9.25 \times 10^{10} \ J$
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