Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - For Thought and Discussion - Page 141: 4

Answer

The answer is below.

Work Step by Step

Recall, $F_{g} = mg$ and $F=ma$. Solving for acceleration, we obtain: $$a = \frac{F}{m} = \frac{mg}{m} =g$$ Thus, all objects fall with constant acceleration, g, regardless of their mass.
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