## Essential University Physics: Volume 1 (3rd Edition)

$1.58\times10^{16} \ kg$
We use the equation for the force of gravity and Newton's second law to find: $ma=\frac{GMm}{r^2}$ $a= \frac{GM}{r^2}$ Thus, if we plot $\frac{G}{r^2}$ versus a, it will be a straight line of slope M. Doing this, we find that the asteroid's mass is $1.58\times10^{16} \ kg$.