Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Section 7.4 - Nonconservative Forces - Example - Page 119: 7.6


$ \frac{1}{2}kx_0^2 = \mu mgd$

Work Step by Step

We know that the block will stop when all of the spring energy becomes mechanical energy, meaning that it will be lost to friction. Thus, we find: $ \frac{1}{2}kx_0^2 = F_f \times d$ $ \frac{1}{2}kx_0^2 = \mu F_n \times d$ $ \frac{1}{2}kx_0^2 = \mu mgd$
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