Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Section 6.5 - Power - Example: 6.7

Answer

a) $97 \ W$ b) $11,000 \ W$

Work Step by Step

We know that the average power is equal to the change in work over the change in time. Thus, we find: a) $P_{avg} = \frac{1300 \times 9.81 \times 55}{2 \times 3600} = 97 \ W$ b) $P_{avg} = \frac{1300 \times 9.81 \times 1500}{.5 \times 3600} = 11,000 \ W$
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