Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Section 6.2 - Work - Example: 6.3

Answer

a) 1510 MJ b) $12^{\circ}$

Work Step by Step

We use the equation for work: $W = F_x\Delta x + F_y\Delta y$ $W = (1.2)(380) + (2.3)(460) = 1510 \ MJ$ We use the Pythagorean theorem to find: $ F = \sqrt{ 1.2^2 + 2.3^2} = 2.59 \ MN$ Thus: $\theta = cos^{-1} (\frac{1510}{2.59 \times 597}) \approx 12^{\circ}$
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