Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Exercises and Problems - Page 105: 35


Please see the work below.

Work Step by Step

(a) We know that $t=1minute =(\frac{1}{60})h$ So the power is $P=\frac{Energy}{time}=\frac{1KWh}{(\frac{1}{60})}=60KW$ (b) Time in hours is $t=1h$ $P=\frac{Energy}{time}$ $P=\frac{1KW.h}{1h}=1KW$ (c) We know that $t=1day=24h$ $P=\frac{Energy}{time}=\frac{1KWh}{24h}=0.042KW$
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