Answer
10 degrees
Work Step by Step
We find the x and y components of the forces:
x: $\frac{mv^2}{r} = F_nsin\theta$
y: $mg = F_ncos\theta$
We set each equation equal to m, and then we set the equations equal to each other:
$\frac{F_nsin\theta\times r}{v^2} = \frac {F_ncos\theta}{g} \\ gF_nsin\theta\times r=v^2F_ncos\theta \\ tan\theta =\frac{v^2}{gr}\\ \theta = \frac{25^2}{9.81 \times 350} \approx 10^{\circ}$
